By the Fundamental Theorem of Calculus, f0(t) = 16 + 15sin ˇt 6 20:1t2: (5) Setting f0(t) = 0 and solving numerically, we nd just one critical point in [0;8] at t 0 ˘6:204. The maximum value of fon [0;8] occurs at an endpoint of the interval or at a critical point, so it must therefore be found at one of three points: at t= 0, t= t 0, or t= 8 ...